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How do I calculate the dosage strength of magnesium citrate if the weight of magnesium carbonate is 15g and citric acid is 22.4G in a 750 ml purified water?

To calculate the dosage strength of magnesium citrate, you need to determine the concentration of magnesium ions in the final solution. Magnesium citrate is a salt formed from magnesium carbonate and citric acid. Here's how you can calculate it:

First, determine the molar mass of magnesium carbonate (MgCO3) and citric acid (C6H8O7).

MgCO3: Mg = 24.305 g/mol, C = 12.011 g/mol, O = 15.999 g/mol

Molar mass of MgCO3 = 24.305 + 12.011 + (3 × 15.999) = 84.313 g/mol

C6H8O7: C = 12.011 g/mol, H = 1.008 g/mol, O = 15.999 g/mol

Molar mass of C6H8O7 = (6 × 12.011) + (8 × 1.008) + (7 × 15.999) = 192.124 g/mol

Calculate the number of moles of magnesium carbonate and citric acid.

Moles of MgCO3 = Mass of MgCO3 / Molar mass of MgCO3

= 15 g / 84.313 g/mol

Moles of C6H8O7 = Mass of C6H8O7 / Molar mass of C6H8O7

= 22.4 g / 192.124 g/mol

Determine the limiting reactant. The reactant that produces the fewer moles of magnesium citrate will be the limiting reactant.

Use stoichiometry to find the number of moles of magnesium citrate produced. The balanced chemical equation for the reaction between magnesium carbonate and citric acid to form magnesium citrate is:

MgCO3 + C6H8O7 → Mg3(C6H5O7)2 + CO2 + H2O

According to the stoichiometry of the reaction, one mole of magnesium carbonate reacts with one mole of citric acid to produce one mole of magnesium citrate.

Calculate the total volume of the solution. Since you're dissolving the reactants in 750 ml of water, the final volume will be 750 ml.

Calculate the concentration of magnesium citrate in the solution.

Concentration (in moles per liter) = Moles of magnesium citrate / Total volume (in liters)

Once you have the concentration of magnesium citrate in moles per liter, you can convert it to other units if needed, depending on the dosage strength you want to calculate.

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