How many milligrams of NADPH will be required to make a 2 millimolar solution with a volume of 100 ml?

To calculate the amount of NADPH required to make a 2 millimolar solution with a volume of 100 ml, you can use the formula:

$\text{Amount (in grams)}=\text{Concentration (in mol/L)}\times \text{Volume (in L)}\times \text{Molecular weight (in g/mol)}$

First, let's convert the concentration from millimolar (mM) to molar (M): $2\text{mM}=2\times 10^{-3}\text{M}$

The molecular weight of NADPH is approximately 744.42 g/mol.

Now, we can plug these values into the formula: $\text{Amount (in grams)}=(2\times 10^{-3}\text{M})\times (100\times 10^{-3}\text{L})\times 744.42\text{g/mol}$

$\text{Amount (in grams)}=2\times 10^{-5}\times 744.42\text{g}$

$\text{Amount (in grams)}=0.0148884\text{g}$

Now, let's convert this amount to milligrams: $0.0148884\text{g}\times 1000\text{mg/g}=14.8884\text{mg}$

So, approximately 14.8884 milligrams of NADPH will be required to make a 2 millimolar solution with a volume of 100 ml.